5x^2+16x-10=0

Solution for 5x^2+16x-10=0 equation:

5x^2+16x-10=0

a = 5; b = 16; c = -10;
Δ = b2-4ac
Δ = 162-4·5·(-10)
Δ = 456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{456}=\sqrt{4*114}=\sqrt{4}*\sqrt{114}=2\sqrt{114}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{114}}{2*5}=\frac{-16-2\sqrt{114}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{114}}{2*5}=\frac{-16+2\sqrt{114}}{10}
$